Section 2.1 Intermediate Algebra

Is x=12 a solution to the equation $\frac {1}{2}x-4=\frac {1}{3}x-2$ ?

$x+2=10$

$2x-3=25$

$-3x-19=5-2x$

$2(x+9) -x=36$

$\frac {x}{3}+\frac {1}{2}=\frac {7}{6}$

$\frac {y-3}{3}-\frac {y-2}{2}=-1$

$2(x+1)=2(x+3)$

$x+x=2x$

$2\left ( \frac {1} {2} x + \frac {3}{2} \right ) - \frac {7}{2}=\frac {3}{2}(x+1)-\left ( \frac {1} {2}x+2 \right )$

$4-6(2x-3)+1=3+2(5-x)$

$-\frac {3}{5}y=9$

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